Why does x86 being little-endian matter when inspecting memory?

For a multi-byte integer stored in memory, little-endian order places the least significant byte at the lowest address. A 32-bit value 0x12345678 therefore appears as bytes 78 56 34 12 in increasing address order. Endianness does not reverse the written digits of a register value or change the order of individual bits inside each byte. It matters for binary formats, network protocols, and debugger output. Use explicit serialization rules rather than assuming the in-memory representation is the correct exte al wire format.